Question

A bucket made of metal sheet is in the form of a cone whose height is 35 cm and radii of circular ends are 30 cm and 12 cm. How many litres of milk it contains if it is full to the brim?

Answer 1

Answer:

51.48 litres

Step-by-step explanation:

∵ The bucket has two circular ends with different radii, it is a frustum of cone

Capacity of Bucket  = Volume of Frustum of cone

$\frac{1}{3}\times \pi \times height ( Radius_1^2  + Radius_2^2 + Radius_1 \times Redius_2)$

$\frac{1}{3}\times \frac{22}{7} \times 35 ( 30^2 + 12^2 + 30 \times 12)$

= (110/3) × (1404)

= 51840 cm³

∵ 1 cm³ = 1/1000 Litres

∴ Capacity of bucket in litres = 51840 × (1/1000)

                                                = 51.48 litres

∴ Bucket contains 51.48 litres milk in it.

Answer 2

$<b><i>$Answer:

It contains 51.480 l of milk if it is full to the brim and the amount received by the person is ₹ 2059.20  .

 

Step-by-step explanation:

SOLUTION :  

Given :  

Radius of the one circular end of the bucket (frustum of cone)( R) =  30 cm

Radius of the other circular end of the bucket (frustum of cone),r = 12 cm

Volume of bucket ( frustum of Cone) = π/3  (R² + r² + Rr) h

= ⅓ × π (30² + 12² + 30× 12)× 35

= ⅓ π (900 + 144 + 360)× 35

= ⅓ π × 1404 × 35

= 22/7 × 468 × 35

= 22× 468 × 5  

= 51480 cm³

= 51.480 l  

[1 cm³ = 1/1000 l]

Volume of bucket = 51.480 l  

It contains 51.480 l of milk if it is full to the brim .

Cost of 1 l of milk = ₹40

Cost of 51.480 l  of milk = ₹40 × 51.48 l  = ₹ 2059.20  

The amount received by the person is ₹ 2059.20  .

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