The sum of the first and third term of an arithmetic progression is 12 and the product of first and second term is 24, then first term is [MP PET 2003]
A) 1 B) 8 C) 4 D) 6
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let the series be (a-d),a, (a+d)
now,
a-d+a+d=12
2a=12
a=6 (this is 2nd term)
now, (a-d)a=24
(6-d)6=24
(6-d)=4
d=2
now (a-d) is first term so (6-2)=4
4 is first term
ans :-(c) 4
now,
a-d+a+d=12
2a=12
a=6 (this is 2nd term)
now, (a-d)a=24
(6-d)6=24
(6-d)=4
d=2
now (a-d) is first term so (6-2)=4
4 is first term
ans :-(c) 4
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