Question

A bucket of height 8 cm with radii of its upper and lower ends are 9 cm and 3 cm respectively. Then slant height of bucket is​

Answer 1

$\tt\pink{\underline{\underline{Given}}}$

→Height of bucket is 8 cm.

→Radius of its upper end is 9 cm.

→Radius of lower end is 3 cm.

$\tt\pink{\underline{\underline{To\:find}}}$

→ Slant height = ?

$\tt\pink{\underline{\underline{Formula\:used}}}$

$→l = \sqrt{h}^{2} + ( r_{1} - r_{2})^{2}$

$\tt\pink{\underline{\underline{Solution}}}$

$→l = { \sqrt{h} }^{2} + ( r_{1} - r_{2})^{2} \\ →l = { \sqrt{8} }^{2} + (9 - 3)^{2} \\ →l = \sqrt{64} + 36 \\ →l = \sqrt{100} \\ →l = 10 \: cm$

$\tt{Hence\:answer\:is}$$\fbox{10\:cm}$

Answer 2

$\tt{\underline{\underline{Given}}}$

→Height of bucket is 8 cm.

→Radius of its upper end is 9 cm.

→Radius of lower end is 3 cm.

$\tt{\underline{\underline{To\:find}}}$

→ Slant height = ?

$\tt{\underline{\underline{Formula\:used}}}$

$→l = \sqrt{h}^{2} + ( r_{1} - r_{2})^{2}$

$\tt{\underline{\underline{Solution}}}$

$→l = { \sqrt{h} }^{2} + ( r_{1} - r_{2})^{2} \\ →l = { \sqrt{8} }^{2} + (9 - 3)^{2} \\ →l = \sqrt{64} + 36 \\ →l = \sqrt{100} \\ →l = 10 \: cm$

$\tt{Hence\:answer\:is}$$\fbox{10\:cm}$