Question

A bucket open at the top is of the form of a frustum of a cone. The diameters of its upper and lower circular end are 30cm and 10cm respectively. If it's height is 24cm, find:-
1) Area of metal sheet used to make the bucket.
2) what is the volume of the bucket. ( Use pi root3= 3.14)

Answer 1

Answer:

Step-by-step explanation:

R1 = 5 cm

R2 = 15 cm

H = 24 cm

Area of metal sheet required = CSA of frustum of cone + area of lower circular end

= 3.14 × ( r1 + r2) × $\sqrt{h^{2} + (r2-r1)^{2}}$ + 3.14×5×5

= 3.14 × 20 × 26 + 3.14 ×25

= 3.14 ( 520 + 25)

= 1711.3 $cm^{2}$

Volume of bucket = $\frac{1}{3} (3.14)(r1^{2} +r2^{2} + r1 r2)$

= $\frac{1}{3} (3.14)(25 + 75 + 225)$

= 340.16667 $cm^{3}$