Question

A buffer solution containing 1 mole of nh4)2so4 and 1 mole of nh4oh the pH solution will be

Answer 1

pH of the buffer solution containing (NH4)2SO4 and NH4 OH is 9.27

Explanation:

The Kb of NH4OH is 1.8 x 10-5

pOH = pKb + log (salt)/(base) ………….. (1)

Now;

pKb = -log Kb

      = - log (1.8 x 10-5)

     = -log (1.8) + -log (-5)

     = - 0.267 + 5

  pKb  = 4.73

Substituting this value in Eq 1

pOH = 4.73 + log (0.1)/0.1

        = 4.73 + log 1

        = 4.73 + 0

pOH = 4.73

pH + pOH = 14

pH = 14 – 4.73

pH = 9.27

The pH of the buffer solution is 9.27

Answer 2

Hope it helps you,friend.