Question

A buffer with a pH of 9.85 contains CH NH, and CH NH,CI in water. What can you
conclude about the relative concentrations of CH NH, and CH,NH,Cl in this buffer? For
CH NH,, PK, = 3.36.​

Answer 1

ANSWER:

pH = 9.85

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 9.85 = 4.15

The solution will be basic buffer.

As,

pOH = pKb + log [ conjugate acid / base ]

4.15 = 3.36 + log [ CH3 NH3 Cl / CH3 NH2 ]

[ CH3 NH3 Cl / CH3 NH2 ] = 6.16

CH3 NH3 Cl > CH3 NH2