Question

A building 20 tall casts a shadow 5 long find the distance between the top of the building and the foot of the shadow

Answer 1

Step-by-step explanation:

let the height of building be AC = 20 and shadow be CB=5

and distance between the top of the building and the foot of the shadow be AB

By Pythagoras Theorem

(AB)2=(AC)2+ (CB)2

=>(AB)2=(20)2+(5)2

=>(AB)2=400+25

=>(AB)2=425

=>AB=√425

=>AB=√5*5*17

.•.AB =5√17

Hence, the distance between the top of the building and the foot of the shadow is 5√17 .