A building contractor undertook to finish a certain work in 162 days and employed 150 men. After 72 days, he found that he had already done 2/3 of the work. How many men can be discharged now, so that the work finish in time?
Answers
Answer:
M1 = 150, M2 = 150 – n, D1 = 72, D2 = 90
W1= 2/3 and W2 = 1/3
According to the formula,
(M1D1) / W1 = (M2D2) / W2
⇒ [150 x 72] / 2 = [(150 – n) x 90] / 1
⇒ (150 x 72) / (2 x 60) = (150 – n)
⇒ (150 – n) = 60
∴ n = 150 – 60 = 90
Answer:
60 Men can be discharged.
Step-by-step explanation:
Lets assume that each man can do 1 unit of work each day. So the total amount/units of work that shall be done by 150 men in 162 days will be = (150×162) which is 24300 units.
According to the problem,
After 72 days 2/3rd of the total work is done.
Therefore, Work done after 72 days = {(2/3)×24300}
= 16200 units.
Work left to be done after 72 days = 24300 units - 16200 units
= 8100 units.
Days left to complete 8100 units of work= (Total amount of days - Days used for completing 2/3 rd of total work)
⇒ 162-72 = 90 days.
So, by the above stated assumption let the men required to complete the remaining 8100 units of work in 90 days be M.
Or, 90×M=8100
Or, M=90.
Total number of men required to complete the remaining work on time is 90.
Hence number of men which can be discharged after the completion of 2/3rd work = (150-Total men required to complete the remaining work in the allotted time)
= 150-90
=60.