A building contractor undertook to finish a certain work in 162 days and employed 150 men. After 72 days, he found that he had already done 2/3 of the work. How many men can be discharged now, so that the work finish in time?
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Answer:
M1 = 150, M2 = 150 – n, D1 = 72, D2 = 90
W1= 2/3 and W2 = 1/3
According to the formula,
(M1D1) / W1 = (M2D2) / W2
⇒ [150 x 72] / 2 = [(150 – n) x 90] / 1
⇒ (150 x 72) / (2 x 60) = (150 – n)
⇒ (150 – n) = 60
∴ n = 150 – 60 = 90
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A building contractor undertook to finish a certain work in 162 days and employed 150 men. After 72 days, he found that he had already done 2/3 of the work. How many men can be discharged now, so that the work finish in time?
hi answere 90
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