Question

The ratio of tree number is 1/2:2/3:1/4. If the value of the biggest number is 32 , find the sum o the the three numbers

Answer 1

Firstly, let us take a common denominator -

$\rightarrow\dfrac{6}{12}:\dfrac{8}{12}:\dfrac{3}{12}$

$\rightarrow6:8:3$

So, let the three numbers be 6k, 8k, and 3k.

The biggest number is 8k.

$\rightarrow8k=32$

$\rightarrow k=4$

So, the sum of three numbers is -

$\rightarrow(6+8+3)\times4=68$

Answer 2

The Sum of the three numbers is 68

Explanation:

Given:

1. The ratio of three numbers is 1/2:2/3:1/4

2. The value of the biggest number is 32

To find:

The sum of the three numbers

==> The ratio of three numbers is 1/2:2/3:1/4

==> Taking LCM of 2,3 and 4

==> LCM of 2,3 and 4 is 12

==> Three numbers is 1/2 (12) : 2/3(12) : 1/4(12)

==> Three numbers is 6:8:3

==> The numbers can be written as 6x:8x:3x

==> let, a= 6x

==> b=8x

==> c=3x

==> The value of the biggest number is 32

==> The biggest number is 8x

==> 8x=32

==> x=32/8

==> x=4

==> Substitute the x value in the numbers

==> a = 6(4)

==> a = 24

==> b = 8(4)

==> b = 32

==> c = 3(4)

==> c = 12

The Sum of the three numbers is

==>a+b+c = 24+32+12 = 68

The Sum of the three numbers is 68