Question

A Bulb emits Light of wavelength 400 nm.If the
total energy emitted by bulb is
3 x 10^-¹⁸ joules, the tortal number of photons
emitted by the bulb will be​

Answer 1

Answer:

mark me brainliest

Explanation:

Power of the bulb = 100 watt = 100Js  

−1

 

Energy of one photon is E=hν=hc/λ

where, h=6.626×10  

−34

Js,c=3×10  

8

ms  

−1

 

Given λ=400nm=400×10  

−9

m

By putting the values, we get

E=6.626×10  

−34

×3×10  

8

/(400×10  

−9

)

E=4.969×10  

−19

J

Number of photons emitted in 1 sec × energy of one photon = power

n×4.969×10  

−19

=100

n=  

4.969×10  

−19

 

100

​  

 

n=2.012×10  

20

photons per sec