Find zeroes of polynomial: p(x) = x²/3 - 4x + 7/3( without using quadratic formula)
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Step-by-step explanation:
Given:-
A polynomial p(x)=x²/3-4x+7/3
To find:-
Find zeroes of polynomial: p(x) = x²/3 - 4x + 7/3( without using quadratic formula).
Solution:-
Given polynomial p(x)=x²/3-4x+7/3
=>(x²-12x+7)/3
To get the zeroes of the polynomial we equate with zero.
=>(x²-12x+7)/3=0.
Completing the square method:
=>x²-12x+7=0
=>x²-12x=-7
=>x²-2(x)(6)=-7
On adding 6² both sides,then
=>x²-2(x)(6)+6²=-7+6²
=>x²-2(x)(6)+6²=-7+36
LHS is in the form of a²-2ab+b²
a²-2ab+b²=(a-b)²
=>(x-6)²=29
=>x-6=±√29
=>x=6±√29
x =6+√29 and 6-√29
Answer:-
Zeroes of the polynomial p(x)=x²/3-4x+7/3 are 6+√29 and 6-√29
Used concept:-
To get zeroes for the given quadratic polynomial we use,
- Factorization method
- Quadratic formula method
- Completing the square method.
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