Question

A bulb is connected to a battery of e.m.f 8V .A steady current 0.3A flows through the circuit . Calculate the total energy supplied by the battery in 10 mins??

Answer 1

Solution :

⏭ Given:

✏ EMF of battery = 8V

✏ Current through circuit = 0.3A

✏ Time interval = 10min

⏭ To Find:

✏ Total energy supplied by the battery.

⏭ Formula:

✏ Formula of energy supplied by battery in given time interval is given by

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{W= V \times I \times t}}}}}} \: \star$

⏭ Terms indication:

✏ W denotes supplied energy

✏ V denotes EMF of battery

✏ I denotes current

✏ t denotes time interval

⏭ Conversation:

✏ 10min = 600s

⏭ Calculation:

$\implies \sf \: W = 8 \times 0.3 \times 600 \\ \\ \implies \: \underline{ \boxed{ \bold{ \sf{ \purple{Energy \: supplies \: by \: battery = 1.44 \: kJ}}}}} \: \gray{ \bigstar}$

⏭ Additional information:

• Electric energy is also given by

W = Pt = VIt = $\sf{I^2}$Rt

Answer 2

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

• Potential difference (v) = 8 volt
• Current (I) = 0.3 amp

We know that , the product of potential difference and current is called electric power

$\large\mathtt{ \fbox{Power = VI}}$

Thus ,

Power = 8 × 0.3

Power = 2.4 watt

And the the rate of work done of unit charge is also known as electric power

$\large \mathtt{ \fbox{Power = \frac{work}{time} }}$

Thus ,

2 4 = work/600

work = 1440 joule

Since , work done = energy

Hence , the total energy supplied by the battery is 1440 Joule

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