Question

- A bulb is emitted electromagnetic radiation of 660 nm
wavelength. The total energy of radiation is 3 x 10- J.
The number of emitted photons will be
(h=6.6 x 10-34 Js, c = 3 × 108 m/s)​

Answer 1

Answer:

it's a simple question do by yourself

Answer 2

Explanation:

E=nhc/Lamda

n=E.lamda/hc

on substitute values we get 10