25. The ratio of the present ages of two brothers is
1:2 and 5 years back the ratio was 1 : 3. What
will be the ratio of their ages after 5 years?
(a) 1:4
(b) 2:3 (c) 3:5
(d) 5:6
Hig!
27.
Answers
Given:
- Ratio of the present ages of two is 1:2.
- Before 5 years, ratio of their ages was 1:3.
To find:
- Ratio of their ages after 5 years?
Solution:
☯ Let Present ages of two brothers be x and 2x.
★ According to the Question:
- Before 5 years, ratio of their ages was 1:3.
Their ages before 5 years,
- Age of first brother = (x - 5) years
- Age of second brother = (2x - 5) years
Therefore,
➯ (x - 5)/(2x - 5) = 1/3
➯ 3(x - 5) = 2x - 5
➯ 3x - 15 = 2x - 5
➯ 3x - 2x = - 5 + 15
➯ x = 10
⠀⠀━━━━━━━━━━━━━━━━━━━━
Therefore,
- Present age of first brother, x = 10 years
- Present age of second brother, 2x = 2 × 10 = 20 years
And,
Their ages 5 years later,
- Present age of first brother = (10 + 5) = 15 years
- Present age of second brother = (20 + 5) = 25 years
Ratio of their ages 5 years later,
➯ 15/25 = 3/5
∴ Hence, Ratio of their ages 5 years later is 3:5.
Answer:
Given :-
- The ratio of the present ages of two brothers is 1:2 and 5 years back, the ratio was 1:3.
To Find :-
- What will be the ratio of their ages after 5 years.
Solution :-
Let, the present age of first brother be x
And, the present age of second brother be 2x
➣ Before 5 years,
First brother age = x - 5 years
And, second brother age will be 2x - 5
➣ Now, the ratio between their age will be,
⇒ =
According to the question,
⇒ =
By doing cross multiplication we get,
⇒ 3(x - 5) = 2x - 5
⇒ 3x - 15 = 2x - 5
⇒ 3x - 2x = - 5 + 15
➠ x = 10
Hence, the required ages will be,
✦ Present age of first brother = x = 10 years
✦ Present age of second brother = 2x = 2(10) = 20 years
Now, ratio of their ages after 5 years,
↦
↦
↦
↦
➥ 3 : 5
The ratio of their ages after 5 years is 3 : 5 .