A bulb is rated 40W and 220V .Find the current drawn by it also find its resistance .If the given bulb is replaced by a bulb of rating 25W and 220v will there be any change in this value of I and R ... Determine the change
Answers
Answered by
21
There is a change in the values of I and R
Attachments:
AbdulNaserShaikh:
kya batyahoon
Answered by
32
Hey dear,
● Answer -
∆I = 0.0682 A
∆R = 727 ohm
● Explanation -
# Given -
P1 = 40 W
P2 = 25 W
V = 220 V
# Formula -
Power of bulb is given by - P = VI
Resistance is calculated by - R = V / I
# Solution -
Initially,
P1 = VI1
40 = 220 × I1
I1 = 0.1818 A
R1 = V / I1
R1 = 220 / 0.1818
R1 = 1210 ohm
Later,
P2 = VI2
25 = 220 × I2
I2 = 0.1136 A
R2 = V / I2
R2 = 220 / 0.1136
R2 = 1937 ohm
Change in current -
∆I = I2 - I1 = 0.1136 - 0.1818 = 0.0682 A
Change in resistance -
∆R = R2 - R1 = 1937 - 1210 = 727 ohm
Hope this helped you...
● Answer -
∆I = 0.0682 A
∆R = 727 ohm
● Explanation -
# Given -
P1 = 40 W
P2 = 25 W
V = 220 V
# Formula -
Power of bulb is given by - P = VI
Resistance is calculated by - R = V / I
# Solution -
Initially,
P1 = VI1
40 = 220 × I1
I1 = 0.1818 A
R1 = V / I1
R1 = 220 / 0.1818
R1 = 1210 ohm
Later,
P2 = VI2
25 = 220 × I2
I2 = 0.1136 A
R2 = V / I2
R2 = 220 / 0.1136
R2 = 1937 ohm
Change in current -
∆I = I2 - I1 = 0.1136 - 0.1818 = 0.0682 A
Change in resistance -
∆R = R2 - R1 = 1937 - 1210 = 727 ohm
Hope this helped you...
Similar questions