Question

A bulb is rated 5.0v ,100mA . calculate the power and resistance

Answer 1

Answer:

P= 0.5 w

R= 50 ohms

Explanation:

V= 5 V

I= 10 mA

R = V/I

R= 5/100×10^-3

=5/0.1

R= 50 ohms

P= VI

P= 5×100×10^-3

P = 0.5 Ohms

Answer 2

Answer:

Power P=0.5 w and Resistance R=50 ohms.

Explanation:

Given:

V=5volts

i=100mA=0.1A

Solution:

Power:

Power P=Vi=5×0.1

             =0.5watt

Resistance:

Resistance R=$\frac{V^{2} }{P}$

                     =$\frac{5^{2} }{0.5}$

                    =50Ω

Therefore, Power P=0.5 w and Resistance R=50 ohms.

• Power is the rate at which work is done in electronics. The barrier put up to the movement of electrons is called resistance.
• Power and resistance have a proportionate relationship. There are two formulas in physics that can be used to relate power and resistance.

What is the connection between resistance and power?

• Power and Resistance are directly related in the equation P =i²R ( Current Constant throughout the circuit ). Power and Resistance are inversely related in the equation P =$\frac{V^{2} }{R}$ . ( Potential difference constant throughout the circuit ). There will surely be opposition wherever there is authority.

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