If an Angle is 3 times its complement angle then find the measure of the pair of angles
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Let the angle be x.
It's complement= 90°-x
3( 90° - x)= x+90°-x
270° -3x =90°
3x = 270°- 90°
X = 60°
The angles are 60° and 30°.
It's complement= 90°-x
3( 90° - x)= x+90°-x
270° -3x =90°
3x = 270°- 90°
X = 60°
The angles are 60° and 30°.
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