Question

a bulb is rated at 200 volt 100 watt what is its resistance ?if 5 Such bulb burnt for 4 hours what is the electric electrical energy consumed? calculate the cost if the rate is 50 Paisa per unit

Answer 1

200÷100×4 may be the answer

Answer 2

Using, P = V²R

we get R = V²P

= (200)²100

= 400

Energy consumed = P x t

= 100 x 4

= 400 Wh

= 0.4 kWh

Cost at the rate of 50 paise per unit

= Rs (0.50 x 0.4)

= Rs 2

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