A bulb is rated at 330v-110v. what do you think is it resistance?
Answers
Answered by
1
I think u have written the values wrong it must be 330W-110V.
then as P=V^2/R
so we get R=V^2/P
on putting values we get
R=36.7 ohm
then as P=V^2/R
so we get R=V^2/P
on putting values we get
R=36.7 ohm
Answered by
1
It can't be 330V as well as 110V.
Both are Voltages.
One should be something else.
Both are Voltages.
One should be something else.
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