Question

A bulb is rated at 330v- 110w. what do you think is its resistance? three such bulbs burn for 5hrs at a stretch. what is the energy consumed? calculate the cost in rupees if the rate is 70 paise per unit?

Answer 1

Refer to this
https://brainly.in/question/1222651

Answer 2

Answer: The correct answers are 990 ohm, 1650 units and Rs 1155.

Explanation:

The expression for power in terms of voltage and resistance is as follows;

$P=\frac{V^{2}}{R}$

Here, P is the power, V is the voltage and R is the resistance.

It is given in the problem that A bulb is rated at 330 V- 110 W.

Rearrange the above expression to get the value of resistance.

$R=\frac{V^{2}}{P}$

Put V= 330 V and P= 110 W.

$R=\frac{(330)^{2}}{110}$

$R= 990 ohm$

The expression for the energy consumed in terms of power is as follows;

E= Pt

Here, E is the energy consumed and t is the time taken.

Calculate the energy consumed by three bulbs.

E= 3Pt

Put P= 110 W and t= 5 h.

E= 3(110)5

E= 1650 units

Calculate the cost in rupees if rate is 70 paise per unit.

The cost in rupees= 70 paise (1650)

The cost in rupees= Rs 1155