Physics, asked by jinanjomon7566, 1 year ago

a bulb of 100 watt and 40 watt are connected in series which will be brighter

Answers

Answered by lalla129
1
Suppose you have 2 bulbs, one rated 240V 60W and the other rated 240V 100W. These ratings mean that when you apply a voltage of 240V to each, they emit 60W and 100W of light power respectively.

The 100W bulb is brighter when they are connected in parallel - when they both have the same voltage of 240V across them. But when they are connected in series they have the same current flowing through them; the voltage across each is different. The power dissipated in each bulb is I2RI2R where II is current and RR is resistance. So when the current is the same the bulb with greater resistance emits more light power and is brighter.

Which bulb has more resistance? You can get the resistance of the bulb from the rating using formula P=V2RP=V2R. VV is the same for both bulbs so the resistances are inversely proportional to the power ratings : R60/R100=P100/P60=100/60R60/R100=P100/P60=100/60. The 60W bulb has the higher resistance. Therefore when the same current flows through both (eg when connected in series) the 60W bulb is brighter.

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Answered by dewangNASA
0
If the light bulbs are connected in parallel, the current flowing through the light bulbs combine to form the current flowing in the battery, while the voltage drop is 6.0 V across each bulb and they all glow. ... One bulb burning out in a series circuit breaks the circuit.

so; 100 watt bulb will use up the energy of 40 watt bulb and 100 watt bulb will glow brighter.

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