Question

A bulb of resistance 400l is connected to 200 V mains . Calculate the magnitude of current​

Answer 1

Answer :

• Magnitude of current is 0.5 A

Explanation :

• Resistance (R) = 400 ohms
• Potential Difference (V) = 200 V

As we know that from the Ohm's Law :

$\longrightarrow \sf{V \: \propto \: I} \\ \\ \longrightarrow \sf{V \: = \: RI}$

Potential Difference is directly proportional to the current. On removing the proportionality symbol here comes a constant known as Resistance. (R)

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Now, use Ohm's Law

⇒V = IR

⇒I = V/R

⇒I = 200/400

⇒I = 0.5

$\therefore$ Magnitude of Current is 0.5 A

Answer 2

Answer:

0.5 A

Explanation:

Given :

P.d. V = 200 V

Resistance R = 400 Ω

We're asked to find current I .

From ohm's law we have :

V = I R

= > I = V / R

Putting values here we get :

= > I = 200 / 400 A

= > I = 2 / 4 A

= > I = 0.5 A

Therefore , magnitude of current​ is 0.5 A.