Question

a bulb of unknown volume containing a gas at 1 atm is connected to a evacuated bulb of 0.5L capcity on opening the stop cork the pressure of whole system become 570mm. find volume of bulb.
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Answer 1

Answer:                                                                                                                    

​1 atm = 101325 Pa

P1V1 = P2V2

101325 x V = 7.58 x 104 x (V + 0.5)

101325V - 75800V = 37900

V = 37900/25525

V = 1.48 L

Explanation: Hope it helps you