a bulb of unknown volume containing a gas at 1 atm is connected to a evacuated bulb of 0.5L capcity on opening the stop cork the pressure of whole system become 570mm. find volume of bulb.
Answers
Answered by
5
Answer:
1 atm = 101325 Pa
P1V1 = P2V2
101325 x V = 7.58 x 104 x (V + 0.5)
101325V - 75800V = 37900
V = 37900/25525
V = 1.48 L
Explanation: Hope it helps you
Similar questions