Question

A bulb operated for 1minute draws a current of 2A when connected to a potential difference of 10 V. Calculate the electrical energy transferred.

Answer 1

Given ,

• Current (I) = 2 amp
• Potential difference (v) = 10 v
• Time (T) = 1 min or 60 sec

We know that ,

The product of potential difference and current is called electric power

$\large\boxed{ \sf{P = VI}}$

Thus ,

P = 6 × 10

P = 60 watt

Now , the formula of electrical energy is given by

$\large\boxed{ \sf{Electrical\: energy = P \times T}}$

Thus ,

Electrical energy = 60 × 60

Electrical energy = 3600 joule

$\sf \therefore \underline{The \: electrical \: energy \: transferred \: is \: 3600 \: J}$