A bulb rated 60 watt at 220 volt is connected across a household supply of alternatin voltage of 220 v . Calculate the maximum instantenious couurnt through the filament
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P = 60W
V = 220 V = E
R = V2/P = (220 x 220)/60 = 806.67
e=√2 ×V
=1.414×220
=311.08
I=e/R
=311.08/806.67
=0.385A
V = 220 V = E
R = V2/P = (220 x 220)/60 = 806.67
e=√2 ×V
=1.414×220
=311.08
I=e/R
=311.08/806.67
=0.385A
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