A bullet fired at an angle of 600 with vertical hits the ground at a distance of 2 km. calculate the distance at which the bullet will hit the ground when fired at an angle of 450, assuming the speed to be the same.
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Angle with horizontal = 30°
R ∝ Sin(2θ)
R1/R2 = Sin(2θ1) / Sin(2θ2)
R2 = R1 * Sin(2θ2) / Sin(2θ1)
R2 = 2 * Sin(90) / Sin(60)
R2 = 4/sqrt(3) km
Distance it hits the ground when fired at angle 45° is 4/sqrt(3) km.
R ∝ Sin(2θ)
R1/R2 = Sin(2θ1) / Sin(2θ2)
R2 = R1 * Sin(2θ2) / Sin(2θ1)
R2 = 2 * Sin(90) / Sin(60)
R2 = 4/sqrt(3) km
Distance it hits the ground when fired at angle 45° is 4/sqrt(3) km.
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