Question

A bullet fired into a block loses one fourth its velocity after moving 0.9 m. Before it comes to rest, what distance will be travelled by bullet?​

Answer 1

Answer:

0.125 m approx

Explanation:

first we calc the deaccelration constant which can be easily found out bt equation

${v}^{2} = {u}^{2} + 2as$

as we know it travels 0.9m after which it's velocity become3/4v2

then we by again using the above formula we be able to find the distance it traveled before coming to rest. but now we have deaccelration constant.

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