A bullet fired with a speed of 50 m/s is stopped at a depth of 10 cm by a wall. what is the retardation offered by the wall
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a/q. initial speed(u)= 50m/s
final speed (v) = 0m/s
distance travelled = 10cm = 0.1 m
now from the relation,
v^2 = u^2+2as
(0)^2 = (50)^2 + 2×(-a)× 0.1
2500=2a/10
2a=25000
a= 12500 m/s^-2 = retardation
here -a is used because there is retardation instead of acceleration
final speed (v) = 0m/s
distance travelled = 10cm = 0.1 m
now from the relation,
v^2 = u^2+2as
(0)^2 = (50)^2 + 2×(-a)× 0.1
2500=2a/10
2a=25000
a= 12500 m/s^-2 = retardation
here -a is used because there is retardation instead of acceleration
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