A length of a rectangle is 7m more than its bredth.if the perimeter 50m.find the length and breadth of the rectangle
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let the breadth be x.
and the length is x+7.
from the question,
perimeter of rectangle=2(l+b)
50=2(x+7+x)
50=2(2x+7)
50=4x+14
50-14=4x
4x=36
x=36/4
x=9
breadth=9m
length=x+7
=9+7
=16m
and the length is x+7.
from the question,
perimeter of rectangle=2(l+b)
50=2(x+7+x)
50=2(2x+7)
50=4x+14
50-14=4x
4x=36
x=36/4
x=9
breadth=9m
length=x+7
=9+7
=16m
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Answered by
1
heya
lets, lenght = x+7
Breadth = x
peri. of rectangle =2(l+b)
hence,
50=2((x+7)+x)
50= 2(2x+7)
50= 4x+14. [2×2x+7×2=4x+14]
50-14=4x
4x= 36 => x=34/6 => x=9.
now,
Length = x+7
Breadth = 9
7x+9
x= 9+7
x = 16m.
therefore, breadth is 9m & lenght is 16m.
thank you, i hope this helps you.
lets, lenght = x+7
Breadth = x
peri. of rectangle =2(l+b)
hence,
50=2((x+7)+x)
50= 2(2x+7)
50= 4x+14. [2×2x+7×2=4x+14]
50-14=4x
4x= 36 => x=34/6 => x=9.
now,
Length = x+7
Breadth = 9
7x+9
x= 9+7
x = 16m.
therefore, breadth is 9m & lenght is 16m.
thank you, i hope this helps you.
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