Question

A bullet fired with a velocity 40 m/s from a of gun of mass 40 kg. Find recoil velocity gun if the mass of bullet is 0.2kg.​

Answer 1

Answer:

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Explanation:

Let velocity of gun is v.

There is no external force acting, so linear momentum will conserve.

Before the firing, Linear Momentum =0

After the firing, Linear momentum =0.04×400+10×v

⇒0.04×400+10×v=0 ⇒v=−1.6m/s

Hence, 1.6m/s opposite to the direction of the bullet.

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Answer 2

Answer:

A bullet fired with a velocity 40 m/s from a gun of mass 40 kg. The recoil velocity of the gun if the mass of the bullet is 0.2kg. is 0.2 m/s

Explanation:

Let m be the mass and v be the velocity of an object,

momentum (P) is given by,

P = mv   ...(1)

Given,

Mass of the bullet  ( $m_{1}$ )  = 0.2 kg

Mass of the gun     ( $m_{2}$ )  =  40 kg

velocity of bullet     ( $v_{1}$ )   =  40 m/s

Let recoil velocity of gun be $v_{2}$ ,

From equation (1),

The momentum of bullet  =  $m_{1} v_{1}$

The momentum of gun     =  $m_{2}v_{2}$

According to the law of conservation of momentum,

if there is no external force,

The momentum of bullet   =  momentum of the gun

Then,

$m_{1} v_{1} = m_{2}v_{2}$

Rearranging the above equation to find out $v_{2}$

$v_{2} = \frac{m_{1}\ v_{1}}{m_{2}}$

$v_{2} = \frac{0.2\times40}{40}$

     = 0.2 m/s

Ans :

Recoil velocity of the gun = 0.2 m/s