A bullet Going with a speed 350m/s enter a concrete wall and penetrate a distance of 5.0cm before coming to rest. Find the deceleration.
Answers
Answered by
4
the initial velocity is 350m/s.
final velocity=0 because bullet stops.
distance=5cm=0.05m.
using the formula v^2=u^2-2as
0=(350)^2-2a(0.05).
122500=0.1a
a=1225000m/s^2
final velocity=0 because bullet stops.
distance=5cm=0.05m.
using the formula v^2=u^2-2as
0=(350)^2-2a(0.05).
122500=0.1a
a=1225000m/s^2
Answered by
6
@ Heya friend.....@
================
Have a look for your in the above pic:-----
Hope it will help you!!
Thanks!!
========
================
Have a look for your in the above pic:-----
Hope it will help you!!
Thanks!!
========
Attachments:
Similar questions