A car accelerates uniformly from 18 km per hour to 36 km per hour in 5 seconds calculate the acceleration and the distance covered by the car in the that time
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HEYA!
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Given that ,
Initial velocity u = 18 km/hr = 5 m/s
Final velocity v = 36 km/hr = 10m/s
Time = 5 seconds
Acceleration a =?
Distance s = ?
Using first equAtion of motion ,
V = U + AT
10=5 +5a
A= 1 ms-2.
Now using second equation of motion
S = 5 × 5 + 1/2 × 1 × 25
S = 25 + 12.5
S = 37.5m
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--------
-----------------------------------------------------------------------------------------------------
Given that ,
Initial velocity u = 18 km/hr = 5 m/s
Final velocity v = 36 km/hr = 10m/s
Time = 5 seconds
Acceleration a =?
Distance s = ?
Using first equAtion of motion ,
V = U + AT
10=5 +5a
A= 1 ms-2.
Now using second equation of motion
S = 5 × 5 + 1/2 × 1 × 25
S = 25 + 12.5
S = 37.5m
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