a bullet has mass 10 g is fired from a gun mass 4kg if bullet moves speed 200m/s the gun will move back ith a speed
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ANSWER
Conservation of linear momentum gives,
m
1
v
1
+m
2
v
2
=0
m
1
v
1
=−m
2
v
2
v
1
=
m
1
−m
2
v
2
Given, m
1
=10g=(
1000
10
)kg,
m
2
=1 kg,
v
2
=−5m/s
∴v
1
=
10/1000
+1×5
or v
1
=500m/s.
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