Math, asked by arorakhushi821, 9 months ago

Prove that (a+b+c) ³-a³-b³-c³= 3(a+b) (b+c) (c+a)

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Answered by raviparmar2002

1

Step-by-step explanation:

note that (a+b+c)³ = a³ + b³ + c³ + 3(a+b)(b+c)(c+a)

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