A bullet having a mass of 10 g and
moving with a speed of 1.5 m/s,
penetrates a thick wooden plank of
mass 90 g. The plank was initially
at rest. The bullet gets embedded in
the plank and both move together.
Determine their velocity.
Answers
Step-by-step explanation:
mass of bullet=10g=0.01kg
velocity of bullet=1.5
s
m
mass of plank=90g=0.09kg
Total momentum before collision=mass of plank × velocity
=0.01×1.5+0.09×0=0.015kg
s
m
Total momentum after collision=(mass of bullet +mass of plank )× velocity
=0.1kg×V=0.1Vkg
s
m
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kg
s
m
=0.1vkg
s
m
velocity acquired by the plank and the bullet=0.15
s
m
Answer:
mass of bullet=10g=0.01kg
velocity of bullet=1.5
s
m
mass of plank=90g=0.09kg
Total momentum before collision=mass of plank × velocity
=0.01×1.5+0.09×0=0.015kg
s
m
Total momentum after collision=(mass of bullet +mass of plank )× velocity
=0.1kg×V=0.1Vkg
s
m
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kg
s
m
=0.1vkg
s
m
velocity acquired by the plank and the bullet=0.15
s
m