A bullet having a mass of 10g and moving with a speed of 1.5 m/s,penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both move together.Determine their velocity.
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Answered by
7
m1v1 = (m1 + m2)v
v = m1v1/(m1 + m2)
v = 10*10^-3 * 1.5 / ((10 + 90)*10^-3)
v = 0.15 m/s
Their velocity is 0.15m/s
v = m1v1/(m1 + m2)
v = 10*10^-3 * 1.5 / ((10 + 90)*10^-3)
v = 0.15 m/s
Their velocity is 0.15m/s
Answered by
11
☆ Hey! ☆
Answer - 0.15 m/s.
See the attachment.
Answer - 0.15 m/s.
See the attachment.
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