Question

A bullet having a mass of 10g and moving with a speed of 1.5 m/s,penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both move together.Determine their velocity.

Answer 1

m1v1 = (m1 + m2)v
v = m1v1/(m1 + m2)
v = 10*10^-3 * 1.5 / ((10 + 90)*10^-3)
v = 0.15 m/s

Their velocity is 0.15m/s

Answer 2

☆ Hey! ☆

Answer - 0.15 m/s.

See the attachment.