A bullet having a mass of 10g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900g. The plank was initially at rest . the bullet gets embedded in the plank and both move together. Determine their velocity. (FOLLOW ME FOLLOW BACK)
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Mass of bullet= 10g= 0.01kg
Velocity of bullet= 1.5m/s
Mass of plank= 90g=0.09kg
Total momentum before collision= (mass of plank) x (velocity)
= (0.01x1.5) + (0.09x0)=0.015 kg m/s
Total momentum after collision= (mass of bullet +mass of plank) x (velocity)
=(0.1 kg x V) =0.1 V kg m/s
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
m1v1 = m2V2
0.015kg m/s =0.1 v kg m/s
Thus, velocity acquired by the plank and the bullet = 0.15m/s
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