Question

a bullet hits a sand box with a velocity of 20 m/s and peneyrates up to distance of 6 cm. Find the retardation of bullet in the sand box

Answer 1

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u = 20m/s 
s = 0.06 m 
v= 0 

v² - u² = 2as 

(0)² - (20)² = 2 x 0.06 x a 

a = -400 / 0.24 
a = -1666.6 m/s²
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Answer 2

hi friend,

given u=20m/s

v=0

s=0.06m

we know that v²-u²=2as

-400=2a(0.06)

-200/0.06=a

a=-3333.33m/s²

I hope this will help u ;)