a bullet hits a wall velocity of 20m/s and penetrates it up to a distance of 5cm . find the deceleration of the bullet in the wall
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Answered by
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u= 20 m/s
v= 0
s = 5 cm = 0.05 m
from 3rd equation,
v² -u² = 2as
⇒0 - (20)² = 2×0.05×a
⇒0.1 a = - 400
⇒a = - 4000 m/s²
deceleration will be - 4000 m/s²
v= 0
s = 5 cm = 0.05 m
from 3rd equation,
v² -u² = 2as
⇒0 - (20)² = 2×0.05×a
⇒0.1 a = - 400
⇒a = - 4000 m/s²
deceleration will be - 4000 m/s²
Answered by
142
Hope it helps u
it is my 3 abswer btw
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