a bullet hits a wall with a velocity of 20 m per second and penetrates it up to distance 5 cm. find the deacceleration of the bullet in the wall.
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v = 0
u = 20 m/s
s=5 cm = 0.05 m
Now, v² - u² = 2as
0² - (20)² = 2×a×0.05
0 - 400 = 0.1*a
-400÷0.1 = a
a = 4000 m/s²
u = 20 m/s
s=5 cm = 0.05 m
Now, v² - u² = 2as
0² - (20)² = 2×a×0.05
0 - 400 = 0.1*a
-400÷0.1 = a
a = 4000 m/s²
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