A bullet hits a wall with a velocity of 20 m/s and penetrates it up to a distance of 5 cm. Find the deceleration of the bullet in the wall.
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A bullet hits a wall with a velocity of 20 m/s and penetrates it up to a distance of 5 cm. What is the deceleration of the bullet in the wall?
In general, the deceleration will not be constant, and to that extent cannot be predicted easily. However, if we assume constant deceleration, the average velocity vavg of the bullet will be half of the initial velocity, or 10 m/s. Then, since it travels distance d = 5 cm to come to rest, its deceleration takes total time t :
t=dvavg
=0.0510
=0.005 seconds
Therefore acceleration a is:
a=Δvt
=−200.005
=−4000 m/s 2......
......i hope it's helpful for u.....
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