Question

Two copper wires A and B of equal masses are taken.
The length of A is double the length of B. If the
resistance of the wire A be 160 12, then calculate the
resistance of the wire B.​

Answer 1

Answer:

mass of wire a = mass of wire b

let

length of wire b be l

length of a = 2l

resistance is directly proportional to length and inversely proportional. to area of wire

resistance of a = 2r = 160 ohm

resistance of b = r = 2r/4 = 160 ohm/4= 40 ohm