A bullet hits a wall with a velocity of 20 m/s and penetrates it up to a distance of 5 cm.
Find the deceleration of the bullet in the wall.
Answers
Answered by
1
u=20 m/s
s=5 cm
v=0
v square- u square=2 as
o^0-20^20=2a^5
-400=10 a
a=-40 m/s
s=5 cm
v=0
v square- u square=2 as
o^0-20^20=2a^5
-400=10 a
a=-40 m/s
sabrina789:
thanks
np
wrong its cm
Answered by
3
v^2=u^2+2as
0=400-2a×5
a=40cm/s^2
0=400-2a×5
a=40cm/s^2
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