Question

A bullet hits a wall with a velocity of 20 m/s and penetrates it up to a distance of 5 cm.

Find the deceleration of the bullet in the wall.

Answer 1

Answer:

- 4000 m/s

Explanation:

Here

u = 20 m/s

v = 0 m/s

S = 5 cm = 0.05 m

Using the equation v^2 - u^2 =2as

0^2 - 20^2 = 2*a*0.05

Solving for a, we get a = - 4000 m/s/s