A bullet hits a wall with a velocity of 20 m/s and Patriots it up to a distance of 5 cm. find the declaration of the bullet in the wall
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2
initial velocity u= 20 m/s.
final velocity v= 0 m/s ( comes to stop).
distance S= 5cm= 0.05m.
using equation of motion , v^2-u^2=2as.
a can be found after solving.
final velocity v= 0 m/s ( comes to stop).
distance S= 5cm= 0.05m.
using equation of motion , v^2-u^2=2as.
a can be found after solving.
dasuma:
4000 m/s
sorry 4000 m/s²
Answered by
1
Initial velocity = 20m/s
Final velocity = 0m/s
Distance = 0.05m
So putting the value we get
0 = 400 + 0.1a
-400/0.1 = 4000m/s^2 will be dissceleration.
Final velocity = 0m/s
Distance = 0.05m
So putting the value we get
0 = 400 + 0.1a
-400/0.1 = 4000m/s^2 will be dissceleration.
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