Question

A bullet if mass 20 gram is fired horizontally into a suspended stationary wooden block of mass 380 gram with the velocity of 200 m per second. what is the common velocity of the bullet and the block. If the block and bullet experiences a constant opposing force of 2 Newton , find the time taken to come to rest?
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Answer 1

Answer:

let m is the mass of bullet, m=0.02Kg

mass of block is M=0.5Kg

velocity of bullet with which it strikes u=300m/s

Bullet comes out with velocity V and velocity of block=v

′

h=0.2m

According to work- energy theorem(for the block after the collision):

0−

2

1

M×v

′

2

=mgh

Put all the values and we get v

′

=2m/s

On applying conservation of momentum

mu=Mv

′

+mv

0.02×300=0.5×2+0.02×v

v=250m/s

Answer 2

Explanation:

answer the question please