total energy of a body at rest at a height h from zero level is 80 j. what is the kinetic energy as it falls through a height h/2
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Answer:
Kinetic energy = decrease in potential energy = 37.5 J.
Explanation:
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Answer:
Let a body of mass 'm' placed at a height 'h' above the ground, start falling down from rest. When the body falls from a height h to h/2
the potential energy is given as
mgh
2
The body covers the distance h/2 with a velocity v. We make use of the third equation of motion to obtain velocity of the body.
v²u²: = 2aS
Here, u = 0, a = g and s = x
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V² -0 = 2gh 2 that is v2 gh =
Kinetic energy 1 =
That is, K.E = mgh 2
Hence, at height h/2 the energy possessed is half potential energy and half the kinetic energy.
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