Question

A bullet initially moving with a velocity of 20 meter per second strikes a target and comes to rest after penetrating a distance of 10cm in the target. Calculate the retardation caused by the target​

Answer 1

$\Huge{\underline{\underline{\mathfrak{Question \colon }}}}$

A bullet initially moving with a velocity of 20 meter per second strikes a target and comes to rest after penetrating a distance of 10cm in the target. Calculate the retardation caused by the target.

$\Huge{\underline{\underline{\mathfrak{Answer \colon }}}}$

From the Question,

• Initial Velocity,u = 20 m/s

• Distance,s = 10 cm = 1/10 m

To find

Retardation of the bullet

After the bullet strikes the target it starts losing velocity,it comes to rest » v = 0 m/s

Using the Relation,

$\huge{ \boxed{ \boxed{ \sf{ {v}^{2} - {u}^{2} = 2as}}}}$

Substituting the values,we get :

$\hookrightarrow \: \sf{ {0}^{2} - {20}^{2} = 2 \times \dfrac{1}{10} \times a} \\ \\ \hookrightarrow \: \sf{ - 400 = \dfrac{a}{5} } \\ \\ \hookrightarrow \: \sf{a = - 400 \times 5} \\ \\ \huge{ \hookrightarrow \: \boxed{ \boxed{ \sf{a = - 2 \times {10}^{3} \: m {s}^{ - 2} }}}}$