a bullet is fired at a plank of wood with a speed of 200 m per second after passing through the plant it is producers to 180 metre per second is a bullet of mass M size and same mass but moving with the speed of hundred metre per second is fired at the same plant then the speed of bullet after passing through the plants
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let the retardation is constant(a) then we can use
v2 = u2 + 2as
v2-u2 = 2as ( s is width of plank)
for first bullet , v = 180 , u = 200
1802 - 2202 = 2as ...............1
for second bullet , v=? , u = 100 so
v2 - 1002 = 2as ..............2 (width of plank & resistance remains same)
divide 1/2
1802 - 2002/v2-1002 = 1
v2 = 2400
v = 49m/s
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